Moin,
DIN | ASA
30 | 800
27 | 400
24 | 200
21 | 100
18 | 50
15 | 25
a = 15
b = 25
(1) DIN = a + x * 3
(2) ASA = b * 2 ** x (** = hoch)
aus (1) folgt:
(3) x = (DIN - a) / 3
aus (2) und (3) folgt
(4) ASA = b * 2 ** ((DIN - a) / 3)
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aus (4) folgt:
(5) log (2, ASA/b) = (DIN - a) / 3
also
(6) DIN = a + 3 * log (2, (ASA / b))
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[ log (2, x) = logarithmus von x zur basis 2 = ln x / ln 2 ]
Viele Gruesse,
n.d.p.