Mertin: Frage zum Thema PHP // MySQL

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You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'ttl_users AS ttl_users ON ttl_galleries_nick.user_id = ttl_user

bei:

$letzten30 = mysql_query("SELECT
                            ttl_galleries_nick.uid,
                            ttl_galleries_nick.user_id,
                            ttl_galleries_nick.pic,
                            ttl_galleries_nick.kommentar,
                            ttl_galleries_nick.stamp,
       ttl_users.nick
                        FROM
                            ttl_galleries_nick AS ttl_galleries_nick LEFT ttl_users AS ttl_users ON ttl_galleries_nick.user_id = ttl_users.nick
                        ORDER BY
                            stamp DESC
                        LIMIT
                            30") or die(mysql_error());