Hallo Siechfred.
Also in etwa so:
var menutree = { menu1 : { hasChildren : true,
children : ['child1', 'child2', 'child3'] },
menu2 : { hasChildren : false }
};
for ( var menu in menutree ) {
if(menutree[menu].hasChildren)
alert(menu + ' has children ' + menutree[menu].children);
else
alert(menu + ' has no children');
}
Kürzer:
~~~javascript
var menutree = { menu1 : ['child1', 'child2', 'child3'],
menu2 : null
};
for ( var menu in menutree ) {
if(menutree[menu])
alert(menu + ' has children ' + menutree[menu]);
else
alert(menu + ' has no children');
}
Einen schönen Mittwoch noch.
Gruß, Mathias
--
ie:% fl:| br:< va:) ls:& fo:) rl:( n4:~ ss:) de:] js:| mo:| zu:)
debian/rules
ie:% fl:| br:< va:) ls:& fo:) rl:( n4:~ ss:) de:] js:| mo:| zu:)
debian/rules