AJAX send/receive

[armin]

Hallo Generic1,

das Ergebnis sollte in request.responseText stehen, Grüsse Armin

[code lang=javascript]
function sendRequestToServer(label, timeMsFrom, timeMsUntil) {
    if(request == null)
       createRequest();
       var url = 'ServerServlet';
       request.open('post', url, true);
       request.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
       request.send('...');
       return request.responseText;
       }

/code]