Hallo,
gibt elegantere Wege, aber so dürfte es auch funktionieren:
select sum(x.y) from
(
select sum(r1) from table as y where bedingung1
UNION
select sum(r2) from table as y where bedingung2
UNION
select sum(r3) from table as y where bedingung3
UNION
select sum(r4) from table as y where bedingung4
UNION
select sum(r5) from table as y where bedingung5
)
x;
ungetestet.
lg.