datum in variable

[ItsCooL]

hi
ich weiss das das hier kein shell forum ist, aber ich weiss nicht mehr weiter;

wie kann ich in einerm shell script das aktuelle datum in einer variable ablegen?

mit #!/bin/sh

datum=$(date +%Y%d%m);

funzt es net  -> error: `datum=$' unexpected

kann mir einer helfen ??

cya

Its My Life And Its CooL

[Tobias Weisserth]

Hallo,

Diese Routine liest das Datum aus, formatiert es und speichert es in der Variablen $date

Schneid raus, was Du brauchst und wirf den Rest weg ;-)

Stammt ursprünglich aus dem Formmail Skript von Matt Wright.

Gruß,
Tobias

sub get_date {

# Define arrays for the day of the week and month of the year.           #
    @days   = ('Sunday','Monday','Tuesday','Wednesday',
               'Thursday','Friday','Saturday');
    @months = ('January','February','March','April','May','June','July',
          'August','September','October','November','December');

# Get the current time and format the hour, minutes and seconds.  Add    #
    # 1900 to the year to get the full 4 digit year.                         #
    ($sec,$min,$hour,$mday,$mon,$year,$wday) = (localtime(time))[0,1,2,3,4,5,6];
    $time = sprintf("%02d:%02d:%02d",$hour,$min,$sec);
    $year += 1900;

# Format the date.                                                       #
    $date = "$days[$wday], $months[$mon] $mday, $year at $time";

}

[ItsCooL]

THX

cya

Its My Life And Its CooL

Hallo,

Diese Routine liest das Datum aus, formatiert es und speichert es in der Variablen $date

Schneid raus, was Du brauchst und wirf den Rest weg ;-)

Stammt ursprünglich aus dem Formmail Skript von Matt Wright.

Gruß,
Tobias

sub get_date {

# Define arrays for the day of the week and month of the year.           #
    @days   = ('Sunday','Monday','Tuesday','Wednesday',
               'Thursday','Friday','Saturday');
    @months = ('January','February','March','April','May','June','July',
          'August','September','October','November','December');

# Get the current time and format the hour, minutes and seconds.  Add    #
    # 1900 to the year to get the full 4 digit year.                         #
    ($sec,$min,$hour,$mday,$mon,$year,$wday) = (localtime(time))[0,1,2,3,4,5,6];
    $time = sprintf("%02d:%02d:%02d",$hour,$min,$sec);
    $year += 1900;

# Format the date.                                                       #
    $date = "$days[$wday], $months[$mon] $mday, $year at $time";

}