db ausgabe sortieren

[Der Schwabe]

Hallo Robert

super vielen dank das "as" wars

SELECT $name, sum($zahl1) AS num1 , sum($zahl2) AS num2, avg($num1 / $num2) AS neu
    FROM $table
    WHERE $datum
    GROUP BY $name
    ORDER BY neu DESC

jetzt funzt's

mfG Der Schwabe