nicht angemeldet
daran hab ich auch schon gedacht, aber dann würd ich in der Funktion mit den orginalen Listen arbeiten, oder ich mache mir davon Kopien....mhm.
Richtig
<snippet> aus dem Perl-Cookbook
Problem
You want to pass a function more than one array or hash and have each remain distinct. For example, you want to put the "Find elements in one array but not in another" algorithm from Recipe 4.7 in a subroutine. This subroutine must then be called with two arrays that remain distinct.
Solution
Pass arrays and hashes by reference, using the backslash operator:
array_diff( @array1, @array2 );
Discussion
See Chapter 11, References and Records, for more about manipulation of references. Here's a subroutine that takes array references and a subroutine call that generates them:
@a = (1, 2);
@b = (5, 8);
@c = add_vecpair( @a, @b );
print "@c\n";
6 10
sub add_vecpair { # assumes both vectors the same length
my ($x, $y) = @_; # copy in the array references
my @result;
for (my $i=0; $i < @$x; $i++) {
$result[$i] = $x->[$i] + $y->[$i];
}
return @result;
}
A potential difficulty with this function is that it doesn't check to make sure it got exactly two arguments that were both array references. You could check explicitly this way:
unless (@_ == 2 && ref($x) eq 'ARRAY' && ref($y) eq 'ARRAY') {
die "usage: add_vecpair ARRAYREF1 ARRAYREF2";
}
If all you plan to do is die on error (see Recipe 10.12), you can usually omit this check, since dereferencing the wrong kind of reference triggers an exception anyway.
</snippet>
Bye
Timothy