Hallo Rouven,
also ich kann einfach keinen Fehler finden... in "done.php" lass ich mir $_POST['select'] anzeigen,... negativ?!
//Hier das Skript:
<html>
<head>
<script language= "JavaScript">
function markAll() {
var m1 = document.testform.select1;
m1len = m1.length;
for (i = 0; i < m1len; i++)
m1.options[i].selected = true;
}
</script>
</head>
<body>
<form method="post" name="testform" action='done.php' onsubmit="markall()">
<select name="select1" size="4" multiple>
<option value="A">item1</option>
<option value="B">item2</option>
<option value="C">item3</option>
<option value="D">item4</option>
</select>
<input type="submit" name="OK">
</form>
</body></html>
Merci,
Honda