Tach!
how can I do something like this. With string the path is not working
According to Namespaces and dynamic language features it should ...
$class = 'Myclassname';
$class = '\Application\Modell\'.$table;
$object = new $class($this->getAdapter());... but $class != $table. If this is not the reason please tell what "is not working" exactly means (error message).
dedlfix.
Hi,
you are right first var is $table. The $class is filled with '\Application\Modell\Myclassname' correctly.
The error is
Call to a member function Myclassname() on a non-object
Because the string is not working here. I can not make the full application new now with namespaces ;(
Thank you
Al