Variable aus Link übergeben

[Johanna]

So hol ich mir die Links aus der DB.
Und geb sie aus!

....

<td colspan="2"><strong>Titel:<br>
   <?
    $current_select = "SELECT * FROM mp3 WHERE $i LIKE '$nameInterpret[0]'";
    $current_result = mysql_db_query ($db,$current_select);
     while ($current = mysql_fetch_object ($current_result)) {
      if ($current -> $t != "NULL" && strtolower ($current -> $t) != strtolower ($lastmp3)) {
   ?>
       <a href="<? echo "id" . "=" . $current -> $id; ?>"><? echo $current -> $t; ?></a><br>
      <?
    }
   $lastmp3 = $current -> $t;
   }
   ?>
</td>

....

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        <param name="filename" value="
!!!!!!!!!Hier soll dann die übergebene Variable rein!!!!!!!!!!!!"

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